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Conduction Law

Dimensions of...

Question

Dimensions of specific heat are :

[M L^{2} T^{- 2} K]

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[M L^{2} T^{- 2} K^{- 1}]

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[M L^{2} T^{2} K^{- 1}]

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[L^{2} T^{- 2} K^{- 1}]

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Solution

The correct option is D $[L^{2} T^{- 2} K^{- 1}]$
The specific heat $s$ is the amount of heat $Q$ per unit mass $m$ required to raise the temperature $θ$ by one degree Celsius.
So, $s = \frac{Q}{m θ} = \frac{M L^{2} T^{- 2}}{M K} = [L^{2} T^{- 2} K^{- 1}]$

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Similar questions

P V = n R T

R

[M L^{2} T^{- 2} K^{- 1}]

	Column I (Units)		Column II (Dimensional formulae)
(A)	Pa s	(p)	$[M^{0} L^{2} T^{- 2} K^{- 1}]$
(B)	N m K $^{- 1}$	(q)	$[M L T^{- 3} K^{- 1}]$
(C)	J kg $^{- 1}$ K $^{- 1}$	(r)	$[M L^{- 1} T^{- 1}]$
(D)	W m $^{- 1}$ K $^{- 1}$	(s)	$[M L^{2} T^{- 2} K^{- 1}]$

(\frac{d Q}{d t} = - K A \frac{d T}{d x})

d Q

d t

K

A

d T

d x

\frac{A^{a} B}{C}

A

M L^{2} T^{- 2} K^{- 1}

B

L^{- 1} T^{- 1}

C

M L^{1} T^{- 3} K^{- 1}

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