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Byju's Answer
Standard VII
Physics
Distance
Displacement ...
Question
Displacement of a particle executing SHM is represented by Y = 0.08 sin (3*pi* t + pi/4) metre. Then calculate-Displacement from mean position at t = 7/36 sec (1) 0.04 metre (2) 0.09 metre (2) 0.07 metre (4) 0.01 metre
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Similar questions
Q.
Displacement of a particle executing simple harmonic motion is represented by
Y
=
0.08
sin
⎧
⎩
3
π
t
+
π
4
⎫
⎭
metre. Then calculate:-
(a) Time period.
(b) Initial phase
(c) Displacement from mean position at t =
7
36
sec.
Q.
The displacement of a particle from its mean position (in metre) is given by
y
=
0.2
sin
(
10
π
t
+
1.5
π
)
cos
(
10
π
t
+
1.5
π
)
. The motion of particle is SHM, with time period of (in seconds)
Q.
The displacement of a particle of mass 100 g executing SHM is given by the equation
y
=
0.2
cos
(
100
t
+
π
4
)
metre. Its total energy is :
Q.
The displacement of a particle executing simple harmonic motion is given by equation y=0.3 sin 20
π
(t+0.05) where time t is in second and displacement y is in metre. calculate the values of amplitude, time period initial phase and initial displacement of the particle .
Q.
The displacement of a particle from its mean position (in metres) is given by
y
=
0.2
sin
(
10
π
t
+
1.5
π
)
cos
(
10
π
t
+
1.5
π
)
. The motion of the particle is SHM, with a time period of
(in seconds)
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