Question

$f\left(x\right)=\{\begin{array}{cc}6x^5,& x<0\\ 2a+x,& x\ge 0\end{array}$. be continuous at $x=0$,then the value of $a$ should be

Answer 1

For f(x) to be continuous at x = 0,

$\underset{h\to 0}{lim}f(0+h)=\underset{h\to 0}{lim}f(0-h)$

$\to 2a+0=6(0{)}^5$

$\to a=0$

Thus, The correct answer is 0.