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Question


3+4i+34i3+4i34i=

A
2i
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B
2
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C
2i
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D
2
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Solution

The correct option is A 2i
=3+4i+34i3+4i34i×(3+4i+34i)(3+4i)+34i
=(3+4i+34i)2(3+4i)(34i)
=3+4i+34i+232+428i
=6+108i=2i

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