$H_{3} P O_{4}$ is a tribasic acid and one of its salt is $N a H_{2} P O_{4}$ . What volume of $1 M$ $N a O H$ solution should be added to $12$ g of $N a H_{2} P O_{4}$ to convert it into $N a_{3} P O_{4}$ ?

200

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100

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750

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None of the above

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Solution

The correct option is B $200$ mL
Reaction:
$2 N a O H + N a H_{2} P O_{4} \to N a_{3} P O_{4} + 2 H_{2} O$
$\frac{12}{120} = 0.1$ Mole of $N a H_{2} P O_{4}$
$V \times 1 = 0.1 \times 2$
$V = 0.2 l i t = 200 m l .$

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H_{3} P O_{4}

is a tri basic acid and one of its salt is

N a H_{2} P O_{4}

. What volume in ml of

1

M NaOH solution should be added to

12

g of

N a H_{2} P O_{4}

to convert it into

N a_{3} P O_{4}

$H_{3} P O_{4}$ is a tribasic acid and one of its salt is $N a H_{2} P O_{4}$ . What volume of 1M NaOH solution should be added to 12 g of $N a H_{2} P O_{4}$ to convert it into $N a_{3} P O_{4}$ ?

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N a H_{2} {P O}_{4}

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N a H_{2} {P O}_{4}

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N a_{3} {P O}_{4}

? (at.wt of P=31)

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H3PO4 is a tribasic acid and one of its salt is NaH2PO4. What volume of 1 M NaOH solution should be added to 12 g of NaH2PO4 to convert it into Na3PO4?

The correct option is B 200 mLReaction:2NaOH+NaH2PO4→Na3PO4+2H2O12120=0.1 Mole of NaH2PO4V×1=0.1×2V=0.2lit=200ml.

$H_{3} P O_{4}$ is a tribasic acid and one of its salt is $N a H_{2} P O_{4}$ . What volume of $1 M$ $N a O H$ solution should be added to $12$ g of $N a H_{2} P O_{4}$ to convert it into $N a_{3} P O_{4}$ ?

The correct option is B $200$ mL
Reaction:
$2 N a O H + N a H_{2} P O_{4} \to N a_{3} P O_{4} + 2 H_{2} O$
$\frac{12}{120} = 0.1$ Mole of $N a H_{2} P O_{4}$
$V \times 1 = 0.1 \times 2$
$V = 0.2 l i t = 200 m l .$