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Question


π0tanxsecx+cosxdx=

A
π
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B
π2
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C
π
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D
2π
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Solution

The correct option is B π2

π0tanxsecx+cosxdx

tanxsecx+cosxdx=d(secx)1+sec2x

=tan1(secx)+c

π0tanxsecx+cosxdx=[tan(secx)+c]|π0

=(tan1(secπ)+c)[tan1(sec0)]

=π2


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