$\int_{a}^{b} f (x) = F (b) - F (a)$

Open in App

Solution

$\int_{a}^{b} f (x) = f (b) - f (a)$
L.H.S:- $\int_{a}^{b} f (x) \cdot d x = [f (x)]_{a}^{b}$
$= f (b) - f (a)$ .

Suggest Corrections

Similar questions

\int_{a}^{b} \frac{f (x)}{f (a) + f (a + b - x)} d x = 10

\int_{a}^{b} \frac{f (x)}{f (x) + f (a + b - x)} d x

To verify Rolle's Theorem for f(x) defined in [a, b], we need to show

When M.V.T is verified for f(x) on [a, b] then there exists c such that

A

B

h

F_{A}

A

F_{B}

B

W_{A}

W_{B}

Join BYJU'S Learning Program