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Question

11+sinxdx is equal to
(where C is constant of integration)

A
tanxsecx+C
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B
tanx+secx+C
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C
tan2x+secx+C
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D
tanx+sec2x+C
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Solution

The correct option is A tanxsecx+C
11+sinxdx
Dividing and multiplying by (1sinx)
(11+sinx)(1sinx)(1sinx)dx
{1sin2x=cos2x}
=1sinxcos2xdx
=1cos2xdxsinxcos2xdx
=sec2xdxtanxsecxdx
=tanxsecx+C

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