wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

2sinx+5(2+5sinx)2dx is equal to
(where C is integration constant)

A
cosx2+5sinx+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
cosx2+5sinx+C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
sinx2+5sinx+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
sinx2+5sinx+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B cosx2+5sinx+C
Let I=2sinx+5(2+5sinx)2dx
Dividing numerator and denominator by cos2x, we get
I=2tanxsecx+5sec2x(2secx+5tanx)2dx
Put 2secx+5tanx=t
(2secxtanx+5sec2x)dx=dt
I=dtt2=1t+C
I=12secx+5tanx+C
I=cosx2+5sinx+C

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Standard Formulae 3
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon