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Question

e3xcos4x dx is equal to
( where C is the constant of integration)

A
e3x25(3cos4x+4sin4x)+C
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B
e2x25(3cos4x4sin4x)+C
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C
e3x16(3cos4x+4sin4x)+C
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D
e3x25(4cos4x+3sin4x)+C
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Solution

The correct option is A e3x25(3cos4x+4sin4x)+C
I=e3xcos4xdxI=e3x32+42(3cos4x+4sin4x)+C(eaxcosbx=eaxa2+b2(acosbx+bsinbx))I=e3x25(3cos4x+4sin4x)+C

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