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Question

ex(1+x)sin2(xex)dx=

A
tan(xex)+c
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B
cot(xex)+c
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C
sin(xex)+c
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D
sinex+c
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Solution

The correct option is B cot(xex)+c
let xex =t
(ex+xex)dx =dt
ex(1+x)dx =dt
dtsin2t =cose c2tdt
=cot t +c
=cot (x ex)+c
ex(1+x)sin2(xex)dx =cot (x ex)+c

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