CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

sin5x2sinx2dx is equal to:
(where c is a constant of integration.)

A
x+2sinx+sin2x+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x+2sinx+2sin2x+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2x+sinx+sin2x+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2x+sinx+2sin2x+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x+2sinx+sin2x+c
I=sin5x2sinx2dx
=2sin5x2cosx2sinxdx
=sin3x+sin2xsinxdx
=(3sinx4sin3x)+2sinxcosxsinxdx
=(34sin2x+2cosx)dx
=(32(1cos2x)+2cosx)dx
=(32+2cos2x+2cosx)dx
=(1+2cos2x+2cosx)dx
=x+sin2x+2sinx+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Standard Formulae 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon