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Question

ππ|π|x|| dx is equal to

A
π2
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B
π22
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C
2π2
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D
2π2
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Solution

The correct option is A π2
I=ππ|π|x|| dx
Here, |π|x|| is an even function.

I=2π0|π|x|| dx
=2π0(πx) dx
=2[πxx22]π0
=2[π22]=π2

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