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Question

tan2(3x+5)dx is equal to (where C is the constant of integration)

A
13x+5tan(3x+5)x+C
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B
13tan(3x+5)+x+C
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C
13tan(3x+5)x+C
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D
13x+5tan(3x+5)+x+C
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Solution

The correct option is C 13tan(3x+5)x+C
I=tan2(3x+5)dx=(sec2(3x+5)1)dx=sec2(3x+5)dxdx{sec2(ax+b) dx=1atan(ax+b)+C,a0}=13tan(3x+5)x+C

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