CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

$$\displaystyle \int (x^x)^x (2x \log_e x + x) dx$$ is equal to


A
x(xx)+C
loader
B
(xx)x+C
loader
C
x2.logex+C
loader
D
None of these
loader

Solution

The correct option is B $$(x^x)^x + C$$
We have, $$\displaystyle \int (x^x)^x (2x \log_e x + x) dx$$
                  $$ = \displaystyle \int x^{x^2} (2x \log_e x + x) dx$$
                  $$ = \displaystyle \int 1 . d(x^{x^2}) = x^{x^2} + C = (x^x)^x + C$$

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image