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Question

[1+i32]6+[1i32]6+[1+i32]5+[1i32]5=

A
-1
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B
1
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C
2
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D
none of these
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Solution

The correct option is C 1
[1+i32]6+[1i32]6+[1+i32]5+[1i32]5
=ω6+(ω2)6+ω5+(ω2)5----(1)
Where ω is cube root of unity.
i.e ω3=1 and 1+ω+ω2=0
from (1)
ω6+(ω2)6+ω5+(ω2)5=1+1+ω2+ω=1
Hence, option B.

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