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Question

limxπ2(1tanx2)(1sinx)(1+tanx2)(π2x)3 is

A
0
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B
132
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C
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D
18
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Solution

The correct option is B 132
tan(π4x2)=1tanx21+tanx2
limxπ2tan(π4x2)(1sinx)4(π2x4)(π2x)2

limxπ2tan(π2x2)(1cos(π2x))4.(π4x2)(π2x)2

limxπ2tan(π2x2)2sin2(π4x2)4(π4x2)42(π2x4)2

=14×216=132

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