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Question

limxπ/2(1tanx/2)(1sinx)(1tanx/2)(π2x)3 is equal to

A
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B
1/8
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C
0
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D
1/32
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Solution

The correct option is C 1/32
We have
limxπ/2(1tanx/21+tanx/2){1sinx(π2x)3}
=164limxπ/2tan(π4x2)(π4x2)[1cos(π/2x)](π4x2)2
=1/64×1×2=1/32

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