${log}_{9} 27 - {log}_{27} 9$ = k?
Find 12k?

10

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11

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12

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15

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Solution

The correct option is A $10$
${log}_{9} 27 - {log}_{27} 9 = {log}_{3^{2}} 3^{3} - {log}_{3^{3}} 3^{2}$
$= \frac{3}{2} {log}_{3} 3 - \frac{2}{3} {log}_{3} 3$
$= \frac{3}{2} - \frac{2}{3} = \frac{5}{6}$
Therefore, $12 k = 10$
Ans: 10

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l o g_{9} 27 - l o g_{27} 9

{log}_{9} 27 - {log}_{27} 9 = k

36 k

X	$10$	$11$	$12$	$13$	$14$	$15$	$16$	$17$	$18$
f	$2$	$7$	$10$	$12$	$15$	$11$	$10$	$6$	$3$

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