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Question

loge(n+1)loge(n1)=4a[(1n)+(13n3)+(15n5)+...] Find 8a.

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Solution

log(1+1n)log(11n)=(1n+12n2+13n3+...)(1n+12n213n3+...)
log(n+1)log(n1)=2(1n+13n3+15n5+...)
Ans: 4

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