The correct option is D −0.405+1.57i
If Z is a complex number, the value of ∫2i3dZZ is log Z|2i3
logZ=12ln(x2+y2)+i tan−1(yx)
=log2i−log3
=log(0+2i)−log(3+0i)
=[12ln(0+4)+itan−1(20)]−[12ln(9+0)+itan−1(03)]
=12ln4+itan−1∞−12ln9−0
=ln(4)1/2+itan−1∞−ln(9)1/2
=ln2+iπ2−ln3=(23)+iπ2
=−0.4054+1.57i