Distance between two stations $P$ and $Q$ is $510 k m$ . Two cars start simultaneously from
$P$ and $Q$ towards each other and the distance between them after $8$ hours is $30 k m$ . If the speed of one car is less than the other by $20 k m / h r$ , then the speed of one car can be

40 k m / h r

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52 k m / h r

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60 k m / h r

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48 k m / h r

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Solution

The correct option is A $40 k m / h r$
Let the speed of faster car be $x k m / h r$ speed of other $= (x - 20) k m / h r$ According to the question
$8 x + 8 (x - 20) + 30 = 510$
$\Rightarrow 8 x + 8 x - 160 + 30 = 510$
$\Rightarrow 16 x - 130 = 510$
$\Rightarrow 16 x = 640$
$\Rightarrow x = 40 k m / h r$

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Distance between two stations P and Q is 510 km. Two cars start simultaneously from P and Q towards each other and the distance between them after 8 hours is 30 km. If the speed of one car is less than the other by 20 km/hr, then the speed of one car can be

The correct option is A 40 km/hrLet the speed of faster car be x km/hr speed of other =(x−20)km/hr According to the question 8x+8(x−20)+30=510 ⇒8x+8x−160+30=510 ⇒16x−130=510 ⇒16x=640 ⇒x=40 km/hr

Distance between two stations $P$ and $Q$ is $510 k m$ . Two cars start simultaneously from
$P$ and $Q$ towards each other and the distance between them after $8$ hours is $30 k m$ . If the speed of one car is less than the other by $20 k m / h r$ , then the speed of one car can be