Divide 2x3y−6x2y3+6x2y2 by 2x2y
x − 3y2 + 2y
x − 2y2 + 3y
x − 3y2 + 3y
x − 3y2 − 3y
Given : Divide 2x3y−6x2y3+6x2y2 by 2x2y
Dividing each term separately we get 2x3y2x2y−6x2y32x2y+6x2y22x2y
= x − 3y2 + 3y
(2x−3y)3+(x+3y)3+3(2x−3y)2(x+3y)+3(2x−3y)(x+3y)2=
Divide 2x3y−6x2y3+6x2y2 by 2x2y