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Question

Divide and write the quotient and remainder.
$$(y^2+10y+24) \div (y+4)$$


Solution

(a) Quotient $$=(y+6)$$
Remainder $$=0$$

(b) Quotient $$=(p+4)$$
Remainder $$-17$$

(c) Quotient $$=(4{x}^{2}+18x+75)$$
Remainder $$=300$$

1358359_1193884_ans_52d806344dfa4e60b5a7cee3a6ef6539.PNG

Mathematics

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