CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Divide x(3x227) by 3(x3)


A

x + 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

x2 + 3x

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

x+3x2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

x2 + 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

x2 + 3x


x(3x227)=3x(x29)=3x(x+3)(x3)

3x(x+3)(x3)3(x3)=x(x+3)=x(x+3)=x2+3x.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon