Question

Do these sides form right angle
$2$cm, $2$cm, $5$cm
In the case of right angled triangles, identify the side opposite to right angle.

Answer 1

Let a $\Delta ABC$

Let us consider, the larger side be the hypotenuse and also using Pythagoras theorem,
$(Hypotenuse{)}^2=(Base{)}^2+(Perpendicular{)}^2$
AB=$2$cm, BC=$2$cm, AC=$5$cm

In $\Delta$ABC, $(AC{)}^2=(AB{)}^2+(BC{)}^2$
$(5{)}^2=(2{)}^2+(2{)}^2$
L.H.S$=(5{)}^2=25$
R.H.S$=(2{)}^2+(2{)}^2=4+4=8$
Since, L.H.S$\ne$R.H.S.
Therefore, the given sides are not of the right angled triangle.