Question

Dobereiner arranged similar elements in a group of three ,i.e, triads, on the basis of?

• A. Nearly the same atomic weight
• B. The atomic weight of the third element was approximately the arithmetic mean of the first two elements
• C. The atomic weight of the middle element was approximately the arithmetic mean of the other two elements
• D. Both $\left(a\right)$ and $\left(c\right)$

Answer 1

The correct option is C The atomic weight of the middle element was approximately the arithmetic mean of the other two elements

Dobereiner arranged elements with similar properties in groups of three and showed the atomic weight of the middle element was approximately the arithmetic mean of the other two elements.