Question

Double bond equivalent of given compound is:

Answer 1

By observation, molecular formula of compound is $C_{10}{H}_{10}$
We know,
Double bond equivalent $=\frac{\Sigma n(V-2)}{2}+1$
where,
n $\to$ number of atoms of element
V $\to$ valency of particular element.
So, $\frac{10(4-2)+10(1-2)}{2}+1=\frac{20-10}{2}+1=6$