Question

Draw a parallelogram ABCD in which AB = 6.5 cm, AD = 4.8 cm and ∠BAD = 70°. Measure its diagonals.

Answer 1

Since ABCD is a parallelogram, AB = DC = 6.5 cm and AD = BC = 4.8 cm.
Given:
$\angle \mathrm{A}=70°$

Steps of construction :
1) Draw AD equal to 4.8 cm.
2) Make an angle of 70^° at A and cut an arc of 6.5 cm. Name it B.
3) Cut an arc of 4.8 cm from B and 6.5 cm from D. Name it C.
4) Join AB, BC and CD.
5) Measuring the diagonals AC and BD, we get AC equal to 9.2 cm and BD equal to 6.6 cm.