Draw a $△ A B C$ with sides 6cm, 8cm and 9cm and then construct a triangle similar to $△ A B C$ whose sides are $\frac{3}{5}$ of the corresponding sides of $△ A B C$ .

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Solution

Let's first construct triangle ABC with sides $6$ cm, $8$ cm, $9$ cm
Thus triangle ABC is required trial with scale $= 3 / 5$
Draw any ray AX making an acute angle with AB ON. The sides opposite to the vertices.
$1$ . Draw base AB of side $6$ cm
$2$ . With A as center, and $8$ cm as radius, draw an arc
with B as center, and $9$ cm as radius, drawn an arc
$3$ . Let C be the point where the two arcs intersect. Join AC & BC.

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Draw a △ABC with sides 6cm, 8cm and 9cm and then construct a triangle similar to △ABC whose sides are 35 of the corresponding sides of △ABC.

Draw a $△ A B C$ with sides 6cm, 8cm and 9cm and then construct a triangle similar to $△ A B C$ whose sides are $\frac{3}{5}$ of the corresponding sides of $△ A B C$ .