draw the graph for x +3y =6 2x-3y=12 hence find the area of the region bounded by x=0 , y=0, 2x-3y=1

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x + 3 y = 6; 2 x - 312

x = 0, y = 0

2 x - 3 y = 12

2 x - 3 y + 6 = 0

2 x + 3 y - 18 = 0

y - 2 = 0

Using the method of integration find the area of the region bounded by lines:

2x + y = 4, 3x – 2y = 6 and x – 3y + 5 = 0

Using the method of integration, find the area of the region bounded by lines
2x + y = 4, 3x - 2y = 6 and x - 3y + 5 = 0

2 x + y = 4, 3 x - 2 y = 6

x - 3 y + 5 = 0

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