wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Draw the graph of the following pair of linear equations :
x+3y=6 and 2x3y=2
Find the ratio of the areas of the two triangles formed by first line, x=0,y=0 and second line, x=0,y=0.

Open in App
Solution

First LineSecond Linex+3y=62x3y=12x=63y2x=12+3yx=12+3y2

First line
x630y012

Second line
x630y024


Area of a triangle=12× base × corresponding altitude

Area of ΔAOBArea of ΔAOC=12×OA×OB12×OA×OC

OBOC=24=12

Required ratio = 1:2

flag
Suggest Corrections
thumbs-up
75
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Graphical Solution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon