Question

# Draw the graphs of the equations xâˆ’y+1=0 and 3x+2yâˆ’12=0. Determine the co-ordinates of the vertices of the triangle formed by these lines and the x-axis, and shade the triangular region.

A
A(1,3),B(1,6) and C(4,0)
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B
A(2,5),B(1,6) and C(2,0)
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C
A(2,5),B(1,6) and C(2,0)
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D
A(2,3),B(1,0) and C(4,0)
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Solution

## The correct option is D A(2,3),B(−1,0) and C(4,0)For equation x–y+1=0 or x=y−1, we have following points which lie on the linePlug y=0,1 we getx=0−1=−1x=1−1=0Therefore, the required points are (−1,0),(0,1). For equation 3x+2y–12=0 or y=12−3x2, we have following points which lie on the linePlug x=0,4 we gety=12−02=6y=12−122=0Therefore, the required points are (0,6),(4,0).We can see from the graphs that points of intersection of the lines with the x–axis are (–1,0),(2,3) and (4,0).

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