Draw the graphs of the following equations graphically.
$3 x - 4 y + 6 = 0; 3 x + y - 9 = 0$ .
Also, determine the coordinates of the vertices of the triangle formed by these lines and x - axis.

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Solution

The given
equation is $3 x - 4 y + 6 = 0$ and $3 x + y - 9 = 0$ .
Now, let us find atleast two solutions of each of the above
equations, as shown in the following tables.
Table for $3 x - 4 y + 6 = 0$ or $y = \frac{3 x + 9}{4}$
Now, table for $3 x + y - 9 = 0$ or $y = 9 - 3 x$
Here, the lines intersecting at point C (2, 3).
The coordinates of the verticles of $△ A C D$ are $A (- 2, 0), C (2, 3)$ and $D (3, 0)$

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Draw the graphs of the following equations graphically. 3x−4y+6=0;3x+y−9=0.Also, determine the coordinates of the vertices of the triangle formed by these lines and x - axis.

Draw the graphs of the following equations graphically.
$3 x - 4 y + 6 = 0; 3 x + y - 9 = 0$ .
Also, determine the coordinates of the vertices of the triangle formed by these lines and x - axis.