Question

Due to slipping, points A and B on the rim of the disc have the velocities shownVelocity of centre of disc will be:

A
0.7m/sec
B
0.2m/sec
C
3.75m/s
D
None

Solution

The correct option is C $$3.75 \mathrm { m } / \mathrm { s }$$Angular velocity with respect to $$\begin{array}{l} =\dfrac { { { v_{ 1 } } } }{ r } \\ =\dfrac { { 4.5 } }{ { 0.4 } } \end{array}$$Angular velocity $$w=11.25 rad/s$$If $$A$$ be at rest let a point at distance $$x$$ from $$A$$ has zero velocity,Then,$$\begin{array}{l} { V_{ A } }+kw=0 \\ At\, \, k=0.2 \\ { V_{ C } }={ V_{ A } }+kw \\ =1.5+\dfrac { { 4.5 } }{ 2 } =3.75\, \, m/s \end{array}$$Option $$C$$ is  correct .Physics

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