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Question

During a practice match, a softball pitcher throws a ball whose height can be modeled by the equation h=16t2+24t+1, where h= height in feet and t = time in seconds. How long does it take for the ball to reach a height of 6 feet?

A
2.2 and 3.8 secs
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B
5.4 and 6.2 secs
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C
0.25 and 1.25 secs
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D
7 and 5 secs
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Solution

The correct option is C 0.25 and 1.25 secs
Given height =6feet
16t2+24t+1=6
16t224t+5=0
16t24t20t+5=0
16t24t20t+5=0
4t(4t1)5(4t1)=0
(4t1)(4t5)=0
t=14,54 or 0.25,1.25
So, at time 0.25 secs and 1.25 secs, the ball will be at a height of 6 feet.

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