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Question

During a practice match, a softball pitcher throws a ball whose height can be modeled by the equation h=16t2+24t+1, where h = height in feet and t = time in seconds. How long does it take for the ball to reach a height of 6 feet?


A

2.2 and 3.8 secs

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B

5.4 and 6.2 secs

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C

0.25 and 1.25 secs

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D

7 and 5 secs

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Solution

The correct option is C

0.25 and 1.25 secs


Given Height = 6
16t2+24t+1=6

16t224t+5=0

16t24t20t+5=0

16t24t20t+5=0

4t(4t1)5(4t1)=0

(4t1)(4t5)=0

t=14,54 or 0.25, 1.25

So, at time 0.25 secs and 1.25 secs, the ball will be at a height of 6 feet.


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