During the adsorption of a gas on the surface of a solid, which of the following is true?

Δ G < 0, Δ H > 0, Δ S < 0

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Δ G > 0, Δ H < 0, Δ S < 0

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Δ G < 0, Δ H < 0, Δ S < 0

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Δ G < 0, Δ H < 0, Δ S > 0

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Solution

The correct option is C $Δ G < 0, Δ H < 0, Δ S < 0$
$Δ G < 0$ - process is spontaneous. Because adsorption is exothermic, $Δ H = - v e$ and the entropy decreases since the gas gets ordered, i.e., $Δ S$ is -ve.

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A + B ⟶ 3 C

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