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Question

dydx=ex+y+e-x+y

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Solution

We have,dydx=ex+y+e-x+ydydx=eyex+e-xe-ydy=ex+e-x dxIntegrating both sides, we gete-ydy=ex+e-x dx-e-y=ex-e-x+Ce-x-e-y=ex+CHence, e-x-e-y=ex+C is the required solution.

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