Question

$E_n=-313.6/n^2$ $kcal/mol$. If the value of $E=-34.84$ $kcal/mol$, to which value does '$n$' correspond?

• A. $4$
• B. $3$
• C. $2$
• D. $1$

Answer 1

The correct option is B $3$

$E_n=-\frac{313.6}{n^2}$ kcal/mol......(1)
$E=-34.84$ kcal/mol......(2)
From (1) and (2)
$-\frac{313.6}{n^2}=-34.84$
$n^2=9$
$n=3$