Question

Eddy is one year elder than Sam and Jack is 7 years elder than Sam. If Jack's age is 3 times the age of Eddy, then the age of Sam is .

• A. $3$ years
• B. $2$ years
• C. $4$ years

Answer 1

The correct option is B $2$ years

Let Sam's age be $x$ years.
Accordingly, Eddy's age would be $x+1$ years and Jack's age would be $x+7$ years.
Given that Jack's age is $3$ times the age of Eddy.
$\Rightarrow x+7=3(x+1)$
$\Rightarrow x+7=3x+3$

Step 1: Place unknown terms in one side and constant terms in one side
$\Rightarrow 7-3=3x-x\Rightarrow 4=2x$

Step 2: Divide both the sides of the equation ($2x=4$) by $2$
$\Rightarrow \frac{2x}{2}=\frac{4}{2}$
$\Rightarrow x=2$
The age of Sam is $2$ years old.