Question

Eight taps through which water flows at the same rate can fill a tank in $27$ minutes. If two taps go out of order, how long will the remaining taps take to fill the tank?

Answer 1

Eight taps through which water flows at the same rate can fill a tank in = $27$ minutes.

So, $1$ tap through which water flows can fill a tank in = $27\times 8$ minutes

Given,

Two taps go out of order then,

remaining taps = $8–2=6$ taps

$\therefore$ $6$ taps through which water flows can fill a tank in = $\frac{27\times 8}{6}$ minutes
$=36$ minutes