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Question

Eight taps through which water flows at the same rate can fill a tank in $$27$$ minutes. If two taps go out of order, how long will the remaining taps take to fill the tank?


Solution

Eight taps through which water flows at the same rate can fill a tank in = $$27$$ minutes.
So, $$1$$ tap through which water flows can fill a tank in = $$27 \times 8$$ minutes

Given,
Two taps go out of order then, 
remaining taps = $$8 – 2 = 6$$ taps

$$\therefore$$ $$6$$ taps through which water flows can fill a tank in = $$\dfrac{27 \times 8}6$$ minutes
$$= 36$$ minutes

Mathematics

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