Question

# Eight taps through which water flows at the same rate can fill a tank in $$27$$ minutes. If two taps go out of order, how long will the remaining taps take to fill the tank?

Solution

## Eight taps through which water flows at the same rate can fill a tank in = $$27$$ minutes.So, $$1$$ tap through which water flows can fill a tank in = $$27 \times 8$$ minutesGiven,Two taps go out of order then, remaining taps = $$8 – 2 = 6$$ taps$$\therefore$$ $$6$$ taps through which water flows can fill a tank in = $$\dfrac{27 \times 8}6$$ minutes$$= 36$$ minutesMathematics

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