Electric field close to plane of charge is shown in figure. External electric field in V/m is

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Solution

let external field be $E_{o}$
$E_{1} = E_{o} + \frac{σ}{2 ϵ_{o}} = 20$ --(1)
$E_{2} = \frac{σ}{2 ϵ_{o}} - E_{o} = 5$ --(2)
By (1) - (2) $E_{o}$ = 7.5

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Electric field close to plane of charge is shown in figure. External electric field in V/m is

let external field be Eo E1=Eo+σ2 ϵo=20 --(1) E2=σ2 ϵo−Eo=5 --(2) By (1) - (2) Eo = 7.5

let external field be $E_{o}$
$E_{1} = E_{o} + \frac{σ}{2 ϵ_{o}} = 20$ --(1)
$E_{2} = \frac{σ}{2 ϵ_{o}} - E_{o} = 5$ --(2)
By (1) - (2) $E_{o}$ = 7.5