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Question

Electricity passed through a solution of alcl3 ,13.5gm al is deposited no.of Faraday must be


Solution

the reaction at cathode is 

Al ( 3+) + 3e---------->Al. (n=3)

→applying the equation 

w = E×i×t/F 

by substituting the values 

♦ i × t = 
13.5 /(27/3)×F

=13.5/9 ×F

=1.5 F

I hope this helps :)
 

Chemistry

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