CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500C mol 1)

A
9.65×104sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
19.3×104sec
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
28.95×104sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
38.6×104sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 19.3×104sec
2H2O+2eH2+2OH

1mol H2 requires 2 faraday current

0.01 mol will require =0.02 faraday current.

Q=0.02×96500 C

Q=i×t

i=10 mili ampere =10×103 ampere

Q=10×103×t

0.02×96500=102×t

t=19.30×104 sec

Option B is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Electrochemistry
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon