Empirical formula of a compound is $C H_{2} O$ and its molecular mass is $90$ , the molecular formula of the compound is :

C_{3} H_{6} O_{3}

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C_{2} H_{4} O_{2}

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C_{6} H_{12} O_{6}

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C H_{2} O

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Solution

The correct option is C $C_{3} H_{6} O_{3}$
Empirical formula mass =12+2+16= 30

$n = \frac{M o l a r M a s s}{E m p e r i c a l M a s s} = \frac{90}{30} = 3$

$M o l a r F o r m u l a = (C H_{2} O)_{n} = C_{3} H_{6} O_{3}$

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