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Question

# Energy of an electron is given by E=−2.178×10−18J(Z2n2) wavelength of light required to excite an electron in an hydrogen atom from level n = 1 to n = 2 will be (h=6.62×10−34 J s and c=3.0×108m s−1)

A
1.214×107m
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B
2.816×107m
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C
6.500×107m
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D
8.500×107m
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Solution

## The correct option is A 1.214×10−7mGiven, in the question E=−2.178×10−18J[Z2n2] For hydrogen Z = 1 So, E1=−2.178×10−18J[112]E2=−2.178×10−18J[122] Now, E2−E1 i.e. ΔE=2.178×10−18(112−122)=hcλ2.178×10−18(112−122)=6.62×10−34×3.0×108λ∴λ=1.21×10−7m

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