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Question

# Equal currents are flowing in four infinitely long wires. Distance between any two adjacent wires is same, then Column I Column II1) force on wire 1p) inwards2) force on wire 2q) leftwards3) force on wire 3r) rightwards4) force on wire 4s) zero

A
1q,2r,3q,4r
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B
1p,2q,3p,4r
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C
1q,2p,3q,4p
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D
1p,2r,3p,4r
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Solution

## The correct option is A 1−q,2−r,3−q,4−rLet the distance between each wire be a. For wire-1, the magnetic field due to wire-2, wire-3 and wire-4 respectively is given by, B2=μ0I2πa,B3=μ0I4πa,B4=μ0I6πa |→Bnet|=μ0I2πa−μ0I4πa+μ0I6πa=5μ0I12πa This net field is directed normally inwards. ∴ force on wire-(1) is leftwards. Wire (2) |→B|=μ0I2πa+μ0I4πa−μ0I2πa=μ0I4πa This field is directed normally inwards. ∴ force on wire-(2) will be directed rightwards For wire-3, |→B|=B1−B2+B4=μ0I4πa This field is directed normally inwards. ∴ force on wire (3) will be directed leftwards For wire-4, |→B|=B1+B3+B2=5μ0I12πa This field is directed normally inwards. ∴ the force on wire (4) will be directed rightawards

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