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Question

Equal masses of methane and oxygen are mixed in an empty container at $$25^{\small\circ}C$$. The fraction of total pressure exerted by oxygen is :


A
1/3
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B
1/2
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C
2/3
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D
13×273298
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Solution

The correct option is A $$1/3$$
The fraction of total pressure exerted by oxygen will be equal to mole fraction of oxygen gas present in mixture of $$CH_4$$ and $$O_2$$.
Partial pressure of a component = Mole fraction ×  total pressure 
Partial pressure of $$O_2$$ $$/$$ Total pressure = mole fraction of $$O_2 = \displaystyle \frac {(m/32)}{(m/32+m/16)} = 1/3$$

Chemistry

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