Equal Number of molecules of hydrogen and oxygen are contained in a vessel at one atmospheric pressure. The ratio of the collision frequency of hydrogen molecules to the of oxygen molecules on the container :

1 : 4

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4 : 1

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1 : 16

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16 : 1

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Solution

The correct option is B $4 : 1$
$n_{1} = V_{r m s} / 2 L$ Hydrogen
$n_{2} = V_{r m s} / 2 L$ Oxygen
$n_{1} / n_{2}$ = $V_{r m s}$ of Hydrogen/ $V_{r m s}$ of oxygen

$V_{r m s}$ of Hydrogen/ $V_{r m s}$ of oxygen $= (M_{O} / M_{H})^{1 / 2}$

So $n_{1} / n_{2} = 4 : 1$

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